# How do you solve kx^2-13x=5 where -1/3 is one solution of the equation?

$k {\left(- \frac{1}{3}\right)}^{2} - 13 \left(- \frac{1}{3}\right) = 5$
$\frac{k}{9} + \frac{13}{3} = 5$
$k + 39 = 45 \implies k = 6$