How do you solve #ln 2 + ln x = 5#?

1 Answer
sente
Nov 14, 2015

#x = e^5/2#

Explanation:

We will use the following properties of logarithms:
#ln(x) + ln(y) = ln(xy)#
#e^(ln(x)) = x#

#ln(2) + ln(x) = 5#

#=> ln(2x) = 5# (by the first property)

#=> e^(ln(2x)) = e^5#

#=>2x = e^5# (by the second property)

#=> x = e^5/2#

Related questions
See all questions in Logarithmic Models
Impact of this question
9554 views around the world
You can reuse this answer
Creative Commons License