# How do you solve ln(n^2+12)=ln(-9n-2)?

Aug 4, 2016

$n = - 7$ or $n = - 2$

#### Explanation:

raising the equation to $e$ we can drop the $\log$ so

${n}^{2} + 12 = - 9 n - 2$

${n}^{2} + 9 n - 14 = 0$

$\left(n + 2\right) \left(n + 7\right) = 0$

$n = - 7$ or $n = - 2$ are potential candidates.

#now you plug in and make sure
and it turns out that they both work