Question

How do you solve `ln x=2`?

Answer 1

`x=e^2`

Explanation:

By definition of logarithms,
`y=log_ax iff a^y=x`
Now ln is the natural logarithm and has base e, where `e~~2,71828`
`therefore lnx=2=>log_ex=2`
`thereforex=e^2`