How do you solve $ln x = -3$ ?

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Answer 1 · 2018-07-17T14:21:04

$x=1/e^3$

Given that

$\ln x=-3$

$e^{\ln x}=e^{-3}\quad (\text{raising powers to base e})$

$x=e^{-3}$

$x=1/e^3$

Answer 2 · 2018-07-19T23:34:57

$x=1/e^3$

We want to cancel out the natural log function. To go about doing this, we can apply its inverse, base $e$ to both sides. We get

$e^lnx=e^-3$

This simplifies to

$x=1/e^3$

As a decimal, this is approximately $0.04979$

Hope this helps!

How do you solve ln x = -3 ln x = -3 ?