# How do you solve ln(x-7)=2?

Oct 30, 2016

${e}^{2} + 7$

#### Explanation:

here is how you do it

$\ln \left(x - 7\right) = 2$
$\mathmr{and} , {e}^{\ln \left(x - 7\right)} = {e}^{2}$
$\mathmr{and} , x - 7 = {e}^{2}$
$\mathmr{and} , x = {e}^{2} + 7$