How do you solve #lnx=2.7#?

1 Answer
Jul 10, 2016

Answer:

#x\approx 14.88#.

Explanation:

The operation inverse to the logarithm is the exponential.
Then we can apply the exponential on both side of this equation

#ln(x)=2.7#

#e^(ln(x))=e^2.7#

and, because the exponential is the opposite of the #ln# we have

#x=e^2.7\approx14.88#.