How do you solve $lnx=2.7$ ?

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Answer 1 · 2016-07-10T18:28:06

$x\approx 14.88$ .

The operation inverse to the logarithm is the exponential.
Then we can apply the exponential on both side of this equation

$ln(x)=2.7$

$e^(ln(x))=e^2.7$

and, because the exponential is the opposite of the $ln$ we have

$x=e^2.7\approx14.88$ .

How do you solve lnx=2.7lnx=2.7?