How do you solve #Log_10 x = -2#?

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Answer 1 · 2016-01-29T08:23:50

#x=1/100=0.01#

Start with the given:
This is the logarithmic form:
#log_10 x=-2#

Convert this to exponential form:

#10^-2=x#

#x=1/10^2#

#x=1/100#

#x=0.01#

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