How do you solve #log_10(x+6) + log_10(3x-2)=2#?
I have taken this to a point where you should be able to take over and complete the calculation. The final format is that of a quadratic.
The left hand side (LHS) is stating that you should take logs of 2 numbers. The RHS is just giving a value. So the RHS is the value you get after taking a log.
So before we start we need to ask the question; what is
Rewrite the given question as:
For logs to be added it means that the source is multiplied so we have:
Consider the LHS only
Rewrite equation (1) as
Now you just multiply out the brackets and put it into standard form!
Have a go at finishing that bit.