How do you solve # log_11 (y + 8) + log_11 4 = log_11 60#?
From laws of logs, the log of the sum is the product of the logs.
So left hand side of equation reduces to
#log_11(4y + 32) = log_11(60)#
Now take the anti-log base 11 on both sides to yield:
#4y + 32 = 60#
This is now a normal linear equation in y which may be solved by normal methods to eventually get