Question

How do you solve `log_15(x+2) = 1-log_15 x`?

Answer 1

`x in {3}`

Explanation:

`log_15 (x + 2) = log_15 (15/x)`

`x + 2 = 15/x`

`x^2 + 2x - 15 = 0`

`x = 3` or `x = -5`

But logarithmands are non negative.