Question

How do you solve `log_(27)x = 1-log_(27)(x- 0.4)`?

Answer 1

Given `log_(27)x=1-log_(27)(x-0.4)`
We can substitute `1=log_(27)(27) " since "log_mm=1`

So, `log_(27)x=log_(27)(27/(x-0.4))`
Removing log on both sides, `x=27/(x-0.4)`

I'm sure you can solve the rest of it.