How do you solve #Log(2x-1)=3#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Jothi S. Dec 5, 2015 #x=1001/2# Explanation: #log(2x-1)=3 -># generally log without base consider as common log so the base is 10 Write in exponential form #2x-1=10^3# #2x=1001# #x=1001/2# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 8578 views around the world You can reuse this answer Creative Commons License