# How do you solve log_2x+log_2 3=3?

Aug 21, 2016

I found: $x = \frac{8}{3}$

#### Explanation:

You can condense the two logs and write:
${\log}_{2} \left(3 x\right) = 3$
use the definition of log and write:
$3 x = {2}^{3}$
$3 x = 8$
$x = \frac{8}{3}$

Aug 21, 2016

$x = \frac{8}{3}$

#### Explanation:

As ${2}^{3} = 8$, we have ${\log}_{2} 8 = 3$, hence

${\log}_{2} x + {\log}_{2} 3 = 3 = {\log}_{2} 8$ or

log_2(3×x)=log_2 8 or

$3 x = 8$ or

$x = \frac{8}{3}$