How do you solve log_3 (-4x+354)-log_3 (-2x+2)=3?

1 Answer
Feb 5, 2015

I would use the fact that:
log_aM-log_aN=log_a(M/N)
You get:
log_3(-4x+354)-log_3(-2x+2)=3
Log_3((-4x+354)/(-2x+2))=3
Using the definition of logarithm:
Log_ax=c -> a^c=x

you get:

((-4x+354)/(-2x+2))=3^3=27

and:

-4x+354=27(-2x+2)
-4x+354=-54x+54
50x=-300
x=-300/50=-6