# How do you solve log 3x = log 2 + log (x+5)?

Jan 11, 2016

x = 10

#### Explanation:

using the law that logx + log y = logxy.

on the right hand side : log2 + log(x +5) =log 2(x + 5 )

so we have log3x = log(2x + 10)

$\Rightarrow 3 x = 2 x + 10 \Rightarrow 3 x - 2 x = 10 \Rightarrow x = 10$