Question

How do you solve `log(3x)=log(5)+log(x-4)`?

Answer 1

`x=10`

Explanation:

Using the laws of logs we can simplify the right hand side to :

`log(3x)=log[(5)(x-4)]`

`therefore log(3x)=log(5x-20)`

Now take the antilog base 10 on both sides to obtain

`3x=5x-20`

`therefore x=20/2=10`