How do you solve Log 5x + log x^2 - log x = 5?

1 Answer
Nov 21, 2015

Elementary

Lets recall a few rules;

log a + log b = log ab

log a - log b = log (a/b )

Okay

Log 5x + log x^2 - log x = 5
Log 5x^3 - log x = 5

Log ((5x^3)/x) = 5

Log 5x^2 = 5

Now this is a base 10 logarithm

so 10 ^ 5 = 5 x^2

Solve and you shall get x = +-100sqrt2