How do you solve #log _ 6 (2-x) + log _ 6 (3-4x) = 1#?
1 Answer
May 2, 2018
Using the property
This is the same as saying (2-x)(3-4x)=6
Solving this we get x=0 or x=
Using the property
This is the same as saying (2-x)(3-4x)=6
Solving this we get x=0 or x=