# How do you solve #log _ 6 (2-x) + log _ 6 (3-4x) = 1#?

##### 1 Answer

May 2, 2018

Using the property

This is the same as saying (2-x)(3-4x)=6

Solving this we get **x=0** or **x= #11/4#**

May 2, 2018

Using the property

This is the same as saying (2-x)(3-4x)=6

Solving this we get **x=0** or **x= #11/4#**

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