Question

How do you solve `\log ( x + 12) - \log x = 1`?

Answer 1

`x=4/3`

Explanation:

`log(x+12)-logx=1`

`log((x+12)/x)=1`

`(x+12)/x=10`

`x+12=10x`

`9x=12`

`x=12/9=4/3`