# How do you solve #log(x-15)+logx=2#?

##### 1 Answer

#### Explanation:

Use the log property that

Since no base was specified we assume the base of the logarithm was

We know that

Expand the product and take that 100 to the LHS

Solve the quadratic in your favorite way, by the quadratic formula for example

However, recall that this was originally a logarithmic formula; we can have anything equal to 0 or a negative number in one!

So we know that