# How do you solve #Log(x+2)+log(x-1)=1#?

##### 2 Answers

Apr 15, 2018

see below

#### Explanation:

Using the addition property of logs you know that

this equals log(x+2)(x-1)=1

and using the common log you know that (x+2)(x-1) needs to equal 10 for the equation to be true, (x+2)(x-1)=10 and

this evaluates to (x+4)(x-3)=0, but -4 can't be a solution because that would make one of the original logs undefined.

Apr 15, 2018

Therefore,

since,