How do you solve −log(x) = 5.4?

Jun 22, 2018

$x = {e}^{- \frac{27}{10}} = x$

Explanation:

After5 the Definition

${\log}_{a} \left(b\right) = n$ if ${a}^{n} = b$
we get

$\log \left(x\right) = - \frac{27}{5}$
therefore

$x = {e}^{- \frac{27}{5}}$

Jun 22, 2018

$\approx 3.98 \cdot {10}^{-} 6$

Explanation:

Given: $- \log \left(x\right) = 5.4$

$\implies \log \left(x\right) = - 5.4$

Since there is no base, the assumed base used is base $10$.

So, we get:

${\log}_{10} \left(x\right) = - 5.4$

$x = {10}^{-} 5.4$ (through logarithm definitions)

$\approx 3.98 \cdot {10}^{-} 6$