How do you solve # log x + log 4 = log (x + 9)#?

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Answer 1 · 2015-11-30T23:12:23

Use the properties of logs ...

#logx+log4=log4x=log(x+9)#

Next, set arguments equal to each other ...

#4x=x+9#

Finally, solve for x ...

#3x=9#

ANSWER : #x=3#

hope that helped