# How do you solve logx+log5=1?

Apr 15, 2016

$x = 2$ (Assuming $L o g$ is $L o {g}_{10}$)

#### Explanation:

$L o g \left(x\right) + L o g \left(5\right) = 1$

Applying $L o g \left(a\right) + L o g \left(b\right) = L o g \left(a b\right)$
$\to L o g \left(5 x\right) = 1$
Assuming $L o g$ is $L o {g}_{10}$
$\to 5 x = {10}^{1}$
$5 x = 10$
$x = 2$