# How do you solve m/4<2 or -3+m>7?

Jul 27, 2018

See a solution process below:

#### Explanation:

Solve each inequality for $m$:

Inequality 1:

$\frac{m}{4} < 2$

$\textcolor{red}{4} \times \frac{m}{4} < \textcolor{red}{4} \times 2$

$\cancel{\textcolor{red}{4}} \times \frac{m}{\textcolor{red}{\cancel{\textcolor{b l a c k}{4}}}} < 8$

$m < 8$

Inequality 2:

$- 3 + m > 7$

$- 3 + \textcolor{red}{3} + m > 7 + \textcolor{red}{3}$

$0 + m > 10$

$m > 10$

The Solution Is:

$m < 8$; $m > 10$

Or, in interval notation:

$\left(- \infty , 8\right)$; $\left(10 , + \infty\right)$

Jul 27, 2018

$m < 8$ or $m > 10$

#### Explanation:

For the first inequality

$\frac{m}{4} < 2$, let's multiply both sides by $4$ to get

$m < 8$

For our second inequality, we can add $3$ to both sides to get

$m > 10$

Therefore, the solution to these inequalities is

$m < 8$ or $m > 10$

Hope this helps!