How do you solve #m- 7= \sqrt { 14- 2m }#?

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Answer 1 · 2018-01-25T12:57:21

Solution: #m=7 , m=5#

#m-7 = sqrt(14-2m)# . Squaring both sides we get ,

#(m-7)^2 = (14-2m) or m^2-14m+49 =14-2m# or

#m^2-14m+2m+49-14=0 # or

#m^2-12m+35=0 # or

#m^2-7m-5m+35=0 # or

#m(m-7)-5(m-7)=0 # or

#(m-7)(m-5)=0 :. m=7 , m=5#

Check: When # m=5 #

L.H.S #=5-7 = -2# and R.H.S # =sqrt(14-2m)=sqrt(14-10)# or

R.H.S # =sqrt4=+-2 :.#L.H.S #(-2)# =R.H.S #(-2)#

Solution: #m=7 , m=5# [Ans]