How do you solve #(n-2.2)/-2 = -2.4#?

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Answer 1 · 2017-04-26T14:16:57

See the solution process below:

First, multiply each side of the equation by #color(red)(-2)# to eliminate the fraction while keeping the equation balanced:

#color(red)(-2) xx (n - 2.2)/-2 = color(red)(-2) xx -2.4#

#cancel(color(red)(-2)) xx (n - 2.2)/color(red)(cancel(color(black)(-2))) = 4.8#

#n - 2.2 = 4.8#

Now, add #color(red)(2.2)# to each side of the equation to solve for #n# while keeping the equation balanced:

#n - 2.2 + color(red)(2.2) = 4.8 + color(red)(2.2)#

#n - 0 = 7#

#n = 7#