How do you solve #n+ 2= - 4+ 2n#?

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Answer 1 · 2016-11-23T20:10:25

#n = 6#

Step 1) Move the terms containing #n# to one side of the equation and the constants to the other side of the equation:

#n + 2 - n + 4 = -4 + 2n - n + 4#

#2 + 4 = 2n - n#

Step 2) Combine like terms on each side of the equation:

#6 = (2 - 1)n#

#6 = 1n#

#n = 6#