How do you solve p^2 + 14p - 38=0 by completing the square?

$p = - 7 \pm \sqrt{87}$
${p}^{2} + 14 p = 38$ add 38 to both sides to have all the terms with variables on one side
${p}^{2} + 14 p + 49 = 87$ to complete the square, find half of 14, which is the coefficient of 14p and then square it. Half of 14 is 7, and ${7}^{2}$ is 49, so we add 49 to both sides
${\left(p + 7\right)}^{2} = 87$ factor
$p + 7 = \pm \sqrt{87}$ square root both sides
$p = - 7 \pm \sqrt{87}$ subtract 7 from both sides to solve for p