How do you solve p^2+7p+8=0 using the quadratic formula?

Jul 19, 2017

See a solution process below:

Explanation:

For $a {x}^{2} + b x + c = 0$, the values of $x$ which are the solutions to the equation are given by:

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

Substituting $1$ for $a$; $7$ for $b$ and $8$ for $c$ gives:

$x = \frac{- 7 \pm \sqrt{{7}^{2} - \left(4 \cdot 1 \cdot 8\right)}}{2 \cdot 1}$

$x = \frac{- 7 \pm \sqrt{49 - 32}}{2}$

$x = \frac{- 7 \pm \sqrt{17}}{2}$

Or

$x = \frac{- 7 + \sqrt{17}}{2}$ and $x = \frac{- 7 - \sqrt{17}}{2}$