How do you solve #p=2w+2h# for #w# in terms of #p# and #h#?

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Answer 1 · 2017-05-31T22:20:58

See a solution process below:

First, subtract #color(red)(2h)# from each side of the equation to isolate the #w# term while keeping the equation balanced:

#p - color(red)(2h) = 2w + 2h - color(red)(2h)#

#p - 2h = 2w + 0#

#p - 2h = 2w#

Now, divide each side of the equation by #color(red)(2)# to solve for #w# while keeping the equation balanced:

#(p - 2h)/color(red)(2) = (2w)/color(red)(2)#

#(p - 2h)/2 = (color(red)(cancel(color(black)(2)))w)/cancel(color(red)(2))#

#(p - 2h)/2 = w#

#w = (p - 2h)/2#

Or

#w = p/2 - (2h)/2#

#w = p/2 - (color(red)(cancel(color(black)(2)))h)/color(red)(cancel(color(black)(2)))#

#w = p/2- h#