How do you solve #(p-5)/(3-p)<=0# using a sign chart?

1 Answer
Jul 14, 2017

Answer:

Have a line in the chart for each the numerator and denominator separately, then one for their quotient. The result is between p=3 and p=5, also including p=5.

Explanation:

Since we can tell the sign of a quotient based on the signs of the numerator and denominator we can use this to create the sign chart as shown:

enter image source here

From the singn chart you can see that the graph is below zero (or negative) between p=3 and p=5.
Additionally, we have to investigate the roots to see when the graph is equal to 0, since the question was #<=#.

So at p=3 the denominator is 0 while the numerator is not, resulting in an indefinite solution. (This would appear as an asymptote approaching negative infinity in this case).
At p=5 the numerator is 0, meaning the graph will be equal to 0 as well.

The overall result is the graph is #<= 0# between p=3 and p=5, including p=5, or #] 3, 5]#