Question

How do you solve `r^2+8r+5=0` using the quadratic formula?

Answer 1

Use the quadratic formula.

Explanation:

Think of the coefficient of `r^2` as 1, so really it is `1r^2+8r+5`, now you just plug in those numbers into the quadratic formula. It would be
1:
`(-8+sqrt(8^2-(4)(1)(5)))/(2*1) = -0.68`
2:
`(-8-sqrt(8^2-(4)(1)(5)))/(2*1) = -7.32`

`x= -0.68, -7.32`