How do you solve #(r+3)/(r-4) = (r-5)/(r+4)#?
Eliminate the fractions by cross multiplying:
Distribute each binomial to get two quadratic equations:
Add 9 to both sides:
Subtract 12 from both sides:
Divide both sides by 16:
To check your answer, plug in
From there, just simplify:
First cross multiply to give you a linear equation.
Then make the equation equal zero.