# How do you solve \root[ 3] { x - 6} + 6= - 4?

Nov 26, 2017

$x = - 994$

#### Explanation:

$\setminus \sqrt[3]{x - 6} + 6 = - 4$

Subtract $6$ from both sides:

$\setminus \sqrt[\textcolor{red}{3}]{x - 6} = - 10$

Cube both sides to cancel out the cube root:

${\left(\setminus \sqrt[\textcolor{red}{3}]{x - 6}\right)}^{\textcolor{red}{3}} = {\left(- 10\right)}^{\textcolor{red}{3}}$

Simplifying:

$x - 6 = - 1000$

$\setminus \rightarrow x = - 944$