How do you solve root3(3x)+6=10?

$x = \frac{64}{3}$

Explanation:

We can take the original:

$\sqrt[3]{3 x} + 6 = 10$

and subtract 6 from both sides:

$\sqrt[3]{3 x} = 4$

$3 x = 64$

$x = \frac{64}{3}$

Jun 14, 2018

$x = \frac{64}{3}$

Explanation:

$\sqrt[3]{3 x} + 6 = 10$

$\sqrt[3]{3 x} = 4$

${\left(\sqrt[3]{3 x}\right)}^{3} = {4}^{3}$

$3 x = 64$

$x = \frac{64}{3}$