# How do you solve #s^2-3(s+2)=4# ?

##### 2 Answers

#### Explanation:

First, use the distributive property to simplify

So now the equation is:

Subtract

This equation is now in standard form, or

To factor and solve for

The two numbers that do that are

Therefore, we put it in factored form, or:

Since they multiply up to

Hope this helps!

*Warning: Long answer, but hopefully worth it*

s = -2 or 5

#### Explanation:

Following PEMDAS:

First, let's distribute -3 to s and +2. Remember that distributing means you're multiplying -3 by both terms in the parentheses. You should now have:

Now, because you have no like terms, add six to both sides. You should now have:

This a quadratics equation, and you need to set the equation to 0 in order to solve it. So, subtract 10 from both sides. You should now have:

Now, use the XBOX method. First, we need to multiply our first term by our last term

Now, you have to multiply 2 numbers that get you

1 - 10

2 - 5

-5 and 2 multiply to get you -10, and add to -3, so these are the terms we want to use. You should now have:

#s^2 -5s + 2s - 10 = 0

Now, make a table like this:

```
? ?
? #s^2# -5s
? 2s -10
```

See where the question marks are? You want to find out what multiplies to give you the terms, starting with

```
s ?
s #s^2# -5s
? 2s -10
```

Now, you have two question marks remaining. Since you have s and ? that multiplies to -5s, the ? will be -5 because s * -5 = -5s. Add that in:

```
s -5
s #s^2# -5s
? 2s -10
```

Now, we have one variable left. s * ? = 2s and -5 * ? equals -10. ? will be 2 because s * 2 = 2s and -5 * 2 = -10. So, insert your final variable:

```
s -5
s #s^2# -5s
2 2s -10
```

Now, your equation looks like this: (s + 2)(s - 5) = 0

Isolate each ordered pair and set it to 0 to find out what is s.

(s + 2) = 0; s = -2

(s - 5) = 0; s = 5

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