Question

How do you solve `sin^2x=0` and find all solutions in the interval `0<=x<360`?

Answer 1

`0, 180^@, 360^@`

Explanation:

sin^2 x = 0
sin x = 0
The unit circle gives --> x = 0, `x = 180`, and `x = 360`
Answers for `(0, 360)`:
`0, 180, 360`