How do you solve #( \sin x ) ^ { 2} = 3#? Trigonometry 1 Answer Jim H Jul 31, 2017 There are no real solutions. Explanation: #(sinx)^2 = 3# if and only if #sinx = +-sqrt3# But #sqrt3 > 1# so #sqrt3# cannot be the sine of any real number. (And neither can #-sqrt3#.) Answer link Related questions How do I determine the molecular shape of a molecule? What is the lewis structure for co2? What is the lewis structure for hcn? How is vsepr used to classify molecules? What are the units used for the ideal gas law? How does Charle's law relate to breathing? What is the ideal gas law constant? How do you calculate the ideal gas law constant? How do you find density in the ideal gas law? Does ideal gas law apply to liquids? Impact of this question 196 views around the world You can reuse this answer Creative Commons License