Question

How do you solve `\sqrt { 3n - 1} = \sqrt { 2n + 1}`?

Answer 1

`n = 2`

Explanation:

`sqrt(3n - 1) = sqrt(2n + 1)`

`(sqrt(3n - 1))^2 = (sqrt(2n + 1))^2`

`3n - 1 = 2n + 1`

`n = 2`