# How do you solve sqrt(5x^2 - 40)= 0?

##### 2 Answers
Mar 12, 2018

$x = 2 \sqrt{2}$ and $x = - 2 \sqrt{2}$

#### Explanation:

Square both sides:

$5 {x}^{2} - 40 = 0$

$5 {x}^{2} = 40$

${x}^{2} = 8$

$x = \pm \sqrt{8}$

$x = \pm 2 \sqrt{2}$

Both these solutions are valid as they satisfy the original equation.

Hopefully this helps!

Mar 12, 2018

$x = \pm \sqrt{8}$

#### Explanation:

1. First, square both sides of the equation, so $5 {x}^{2} - 40 = 0$
2. Add $40$ to both sides: $5 {x}^{2} = 40$
3. Divide by $5$ on both sides: ${x}^{2} = 8$
4. Square root on both sides: $x = \pm \sqrt{8}$