How do you solve #\sqrt { 8y + 9} = \sqrt { 7y + 10}#?

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Answer 1 · 2016-12-02T02:10:31

Square both sides to start. #y=1#

We can square both sides:

#sqrt(8y+9)=sqrt(7y+10)#

#(sqrt(8y+9))^2=(sqrt(7y+10))^2#

#8y+9=7y+10#

#y=1#

And we can check the answer:

#sqrt(8(1)+9)=sqrt(7(1)+10)#

#sqrt(17)=sqrt(17)#