How do you solve #\sqrt { 9n } - 2= 4#?

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Answer 1 · 2017-06-18T20:54:34

See a solution process below:

First, add #color(red)(2)# to each side of the equation to isolate the radical while keeping the equation balanced:

#sqrt(9n) - 2 + color(red)(2) = 4 + color(red)(2)#

#sqrt(9n) - 0 = 6#

#sqrt(9n) = 6#

Next, square both sides of the equation to eliminate the radical while keeping the equation balanced:

#(sqrt(9n))^2 = 6^2#

#9n = 36#

Now, divide each side of the equation by #color(red)(9)# to solve for #n# while keeping the equation balanced:

#(9n)/color(red)(9) = 36/color(red)(9)#

#(color(red)(cancel(color(black)(9)))n)/cancel(color(red)(9)) = 4#

#n = 4#