How do you solve #sqrt( x+3)=5#?

3 Answers
Jan 31, 2016

Answer:

#x=22#

Explanation:

Squaring both sides, We get #x+3 = 25 or x=25-3 or x=22# [Answer]

Jan 31, 2016

Answer:

22 :)

Explanation:

We simply do a little algebraic techniques to solve for the value of #x#. First, we must remember the "Golden Rule of Algebra", what ever you do in the one side of the equation, you must do it in the other side of the equation. (Balancing).

#sqrt(x+3) = 5#

we need to isolate the value of #x# to get its value,

to eliminate the square root sign, we need to square both sides, giving:

#x + 3 = 25#

to eliminate the 3 in the Left Side of the Equation, we need to minus #3# in the both sides giving:

#x = 22#

hence, the answer and value of #x# is #22#

Feb 1, 2016

#sqrt(x+3)=5#

Square both sides to remove the radical sign:

#rarr(sqrt(x+3))^2=5^2#

#rarrx+3=25#

#rarrx=25-3=2#