How do you solve #\sqrt { y - 7} + 5= 9#?

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Answer 1 · 2017-06-20T14:09:19

See a solution process below:

First, subtract #color(red)(5)# from each side of the equation to isolate the radical while keeping the equation balanced:

#sqrt(y - 7) + 5 - color(red)(5) = 9 - color(red)(5)#

#sqrt(y - 7) + 0 = 4#

#sqrt(y - 7) = 4#

Next, square both sides of the equation to eliminate the radical while keeping the equation balanced:

#(sqrt(y - 7))^2 = 4^2#

#y - 7 = 16#

Now, add #color(red)(7)# to each side of the equation to solve for #y# while keeping the equation balanced:

#y - 7 + color(red)(7) = 16 + color(red)(7)#

#y - 0 = 23#

#y = 23#