# How do you solve # sqrt3cscx-2=0#?

##### 1 Answer

#### Explanation:

First, let's isolate

#sqrt3cscx - 2 = 0#

#sqrt3cscx = 2#

#cscx = 2/sqrt3#

Now, since we know that

#1/cscx = 1/(2/sqrt3)#

#sinx = sqrt3/2#

Now, we can see that our solution set will be all points where

The two points with a y-coordinate of

Therefore, our solution is:

#{x | x = pi/3, x = (2pi)/3}#

One last touch: remember that the values of all trig functions are the same if you add

#{x | x = pi/3 + 2kpi, " " x = (2pi)/3 + 2kpi}, " for any integer " k#

Or if you REALLY want to translate the last part into fancy math symbols:

#{x | x = pi/3 + 2kpi, " " x = (2pi)/3 + 2kpi}," " forall k in ZZ#

*Final Answer*