How do you solve #T = (4U)/E# for #U#?

1 Answer

When we're asked to solve for a variable, we can do operations to both sides of an equation to isolate the term we're solving for. #(TE)/4=U#

Explanation:

When we solve for something, we want to say that that thing (in this case #U#) equals a combination of all the other things. To do that, we use the tools are our disposal. Let's see where this goes:

Starting with the original:

#T=(4U)/E#

and we want to solve for U. To do that, let's multiply both sides by #E# (which will remove the E from the denominator of the fraction and "move it to the other side" and we can also divide by 4 on both sides (which will "move the 4 to the other side"). Like this:

#Txx(E/4)=(cancel4U)/cancelExx(cancelE/cancel4)#

#(TE)/4=U#