Question

How do you solve `tana+1=0` and find all solutions in the interval `[0,2pi)`?

Answer 1

the solutions are `-pi/4, (3pi)/4` and `(7pi)/4`

Explanation:

`tanalpha+1=0rArrtanalpha=-1rArrtanalpha=-tan(pi/4)`
it is of the form `tanalpha=tank`
the general solution is `alpha=npi+krArralpha=npi-pi/4` since it is given that `alphain[0,2pi)` `rArrn=0,1,2`
on substituting `n=0,1,2rArralpha=pi/4,(3pi)/4 and (7pi)/4`